If f(x)= cases _ t (6^t+10^t)^ 1 t ,&x=0 ^2+4x+C,&x 0 cases is a continuous function

MATHEMATICS · Subjective · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

If f(x)={lim⁡t→∞(6t+10t)1t,x=0x2+4x+C,x≠0f(x)=\begin{cases}\lim_{t\to\infty}(6^t+10^t)^{\frac{1}{t}},&x=0\\x^2+4x+C,&x\neq 0\end{cases} is a continuous function, then minimum value of f(x)f(x) is

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