A particle moves along a straight line with the following velocity schedule: • At it has

PHYSICS · Single correct · CBSE · Physics · Motion · Motion

Problem

A particle moves along a straight line with the following velocity schedule: • At t=0t = 0 it has v=4 m s−1v = 4\,\text{m}\,\text{s}^{-1}. • It increases uniformly to 14 m s−114\,\text{m}\,\text{s}^{-1} in the next 5 s5\,\text{s}. • It maintains this velocity for the following 3 s3\,\text{s}. • Finally, it decreases uniformly to 2 m s−12\,\text{m}\,\text{s}^{-1} in the next 4 s4\,\text{s}. The total displacement of the particle during the 12 s12\,\text{s} motion is (a) 144 m144\,\text{m} (b) 105 m105\,\text{m} (c) 119 m119\,\text{m} (d) 111 m111\,\text{m}

Related theory

Browse the problem library