For the catalyzed reaction products

CHEMISTRY · Single correct · A Level · Chemistry · Rate equations · Rate equations

Problem

For the catalyzed reaction

2\,\mathrm{A}\rightarrow

products, the rate law is

\text{rate}=k'[\mathrm{A}][\mathrm{Z}]

, where

\mathrm{Z}

is a catalyst that remains at constant concentration during the reaction. With

[\mathrm{A}]=0.060\,\text{M}

and

[\mathrm{Z}]=0.0050\,\text{M}

, the initial rate is

3.6\times10^{-4}\,\text{M\,s}^{-1}

. What is the rate when

[\mathrm{A}]

has fallen to 0.020\,M while

[\mathrm{Z}]

is still 0.0050\,M? (a)

3.6\times10^{-5}\,\text{M\,s}^{-1}

(b)

9.0\times10^{-4}\,\text{M\,s}^{-1}

(c)

1.2\times10^{-4}\,\text{M\,s}^{-1}

(d)

3.6\times10^{-4}\,\text{M\,s}^{-1}