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X^2 + 12x + y^2 - 4y + 15 = 0 The equation of a circle in the -plane is shown above
MATHEMATICS · Single correct · GCSE · Mathematics · Graphs · Graphs
Problem
x
2
+
12
x
+
y
2
−
4
y
+
15
=
0
x^2 + 12x + y^2 - 4y + 15 = 0
x
2
+
12
x
+
y
2
−
4
y
+
15
=
0
The equation of a circle in the
x
y
xy
x
y
-plane is shown above. Which of the following is true about the circle? (A) center
(
−
6
,
2
)
(-6, 2)
(
−
6
,
2
)
, radius
=
5
= 5
=
5
(B) center
(
6
,
−
2
)
(6, -2)
(
6
,
−
2
)
, radius
=
5
= 5
=
5
(C) center
(
−
6
,
2
)
(-6, 2)
(
−
6
,
2
)
, radius
=
15
= \sqrt{15}
=
15
(D) center
(
6
,
−
2
)
(6, -2)
(
6
,
−
2
)
, radius
=
15
= \sqrt{15}
=
15
Related theory
Circle (Standard Equation)
Conic Sections
Coordinate Geometry
Equation of a circle
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