Equation of the plane through three points and with position vectors

MATHEMATICS · Single correct · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

Equation of the plane through three points A,BA, B and CC with position vectors −6i+3j+2k-6\mathbf{i} + 3\mathbf{j} + 2\mathbf{k}, 3i−2j+4k3\mathbf{i} - 2\mathbf{j} + 4\mathbf{k} and 5i+7j+3k5\mathbf{i} + 7\mathbf{j} + 3\mathbf{k} is equal to (1) r⋅(i−j+7k)+23=0\mathbf{r} \cdot (\mathbf{i} - \mathbf{j} + 7\mathbf{k}) + 23 = 0 (2) r⋅(i+j+7k)=23\mathbf{r} \cdot (\mathbf{i} + \mathbf{j} + 7\mathbf{k}) = 23 (3) r⋅(i+j−7k)+23=0\mathbf{r} \cdot (\mathbf{i} + \mathbf{j} - 7\mathbf{k}) + 23 = 0 (4) r⋅(i−j−7k)=23\mathbf{r} \cdot (\mathbf{i} - \mathbf{j} - 7\mathbf{k}) = 23

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