For the function f(x)= cases mx+3, & x2 cases determine the ordered pair so that is…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For the function f(x)={mx+3,x<2,5,x=2,x2+n,x>2f(x)= \begin{cases} mx+3, & x<2,\\ 5, & x=2,\\ x^{2}+n, & x>2 \end{cases} determine the ordered pair (m,n)(m,n) so that ff is continuous at x=2x=2. (a) (2,−1)(2,-1) (b) (1,−1)(1,-1) (c) (1,1)(1,1) (d) (2,1)(2,1)

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