MATHEMATICS · Single correct · CBSE · Mathematics · Relations and Functions · Relations and Functions
Problem
Let f:(0,1)→R be defined by f(x)=1−bxb−x, where b is a constant such that 0<b<1. Then,
(1) f is not invertible on (0,1)
(2) f=f−1 on (0,1) and f′(b)=f′(0)1
(3) f=f−1 on (0,1) and f′(b)=f′(0)1
(4) f−1 is differentiable on (0,1)