Let , where the function satisfies for all natural numbers and . Then the natural…

MATHEMATICS · Single correct · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

Let ∑k=110f(a+k)=16(210−1)\sum_{k=1}^{10} f(a+k) = 16(2^{10}-1), where the function ff satisfies f(x+y)=f(x)f(y)f(x+y)=f(x)f(y) for all natural numbers x,yx,y and f(1)=2f(1)=2. Then the natural number aa is: (a) 2 (b) 16 (c) 4 (d) 3

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