CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If tan⁡(x+y)+tan⁡(x−y)=1\tan(x + y) + \tan(x - y) = 1 , then dydx=\frac{dy}{dx} = (a) sec⁡2(x+y)+sec⁡2(x−y)sec⁡2(x+y)−sec⁡2(x−y)\frac{\sec^2(x + y) + \sec^2(x - y)}{\sec^2(x + y) - \sec^2(x - y)} (b) sec⁡2(x+y)+sec⁡2(x−y)sec⁡2(x−y)−sec⁡2(x+y)\frac{\sec^2(x + y) + \sec^2(x - y)}{\sec^2(x - y) - \sec^2(x + y)} (c) sec⁡2(x+y)−sec⁡2(x−y)sec⁡2(x+y)+sec⁡2(x−y)\frac{\sec^2(x + y) - \sec^2(x - y)}{\sec^2(x + y) + \sec^2(x - y)} (d) None of these

Related theory

Browse the problem library