The energy of an electron in the third Bohr orbit of singly-ionised helium (He ) is…

CHEMISTRY · Single correct · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

The energy of an electron in the third Bohr orbit of singly-ionised helium (He+^+) is measured to be −6.04 eV-6.04\,\text{eV}. Using this information, determine the speed of the electron in its first Bohr orbit. Choose the closest value. (a) 2.19×106 m s−12.19\times10^{6}\,\text{m\,s}^{-1} (b) 1.46×106 m s−11.46\times10^{6}\,\text{m\,s}^{-1} (c) 4.38×106 m s−14.38\times10^{6}\,\text{m\,s}^{-1} (d) 8.76×106 m s−18.76\times10^{6}\,\text{m\,s}^{-1}

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