The region enclosed by the curves ,

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

The region enclosed by the curves x=y3+1x = y^{3}+1, x=4x = 4, and y=0y = 0 is revolved about the vertical line x=−2x = -2. What is the volume of the resulting solid? (a) π(3⋅31/3−34/34)\displaystyle \pi\Bigl(3\cdot 3^{1/3}-\dfrac{3^{4/3}}{4}\Bigr) (b) 297π14 31/3\displaystyle \frac{297\pi}{14} \,3^{1/3} (c) π(15⋅31/3−12 34/3−37/37)\displaystyle \pi\Bigl(15\cdot 3^{1/3}-\tfrac12\,3^{4/3}-\tfrac{3^{7/3}}{7}\Bigr) (d) 57π14 34/3\displaystyle \frac{57\pi}{14}\,3^{4/3}

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