A Level

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

MnO4−+8H++5e−⟶Mn2++4H2O\text{MnO}_4^- + 8\text{H}^+ + 5\text{e}^- \longrightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O}; E∘=1.51 VE^\circ = 1.51\text{ V}, MnO2+4H++2e−⟶Mn2++2H2O\text{MnO}_2 + 4\text{H}^+ + 2\text{e}^- \longrightarrow \text{Mn}^{2+} + 2\text{H}_2\text{O}; E∘=1.23 VE^\circ = 1.23\text{ V}, EMnO4−/MnO2∘E^\circ_{\text{MnO}_4^-/\text{MnO}_2} is (a) 1.70 V (b) 0.91 V (c) 1.37 V (d) 0.548 V

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