The line tangent to the graph of a differentiable

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

The line tangent to the graph of a differentiable, one-to-one function ff at x=1x = 1 is given by y=4+2(x−1)y = 4 + 2(x - 1). Which equation represents the line tangent to the graph of the inverse function f−1f^{-1} at x=4x = 4? (a) y−1=2(x−4)y - 1 = 2(x - 4) (b) y−4=12(x−1)y - 4 = \dfrac12(x - 1) (c) y−1=12(x−4)y - 1 = \dfrac12(x - 4) (d) y−1=−12(x−4)y - 1 = -\dfrac12(x - 4)

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