Industrial lubricant is stored in a container shaped like a right frustum of a cone

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

Industrial lubricant is stored in a container shaped like a right frustum of a cone. • The container height is 10 m, the radius at the bottom is 1 m, and the radius at the top is 3 m. • Lubricant is pumped into the container at 0.20 m3^3 min−1^{-1} while simultaneously leaking from a small crack at 0.05 m3^3 min−1^{-1}. • The lubricant’s temperature is rising at 0.30 °C min−1^{-1} due to ambient conditions, and its coefficient of volumetric thermal expansion is 9.5×10−49.5\times10^{-4} °C−1^{-1}. Let h(t)h(t) represent the depth of lubricant (in meters) at time tt minutes, and assume the lubricant is well-mixed so its temperature is spatially uniform. (a) Derive a formula for the radius of the lubricant surface, rr, as a linear function of its depth hh. Briefly justify each step. (b) Write an expression for the net rate of volume change, dVdt\dfrac{dV}{dt}, that accounts for inflow, outflow, and thermal expansion. Express your result in terms of hh and the lubricant’s instantaneous volume VV. (c) Obtain a formula for dhdt\dfrac{dh}{dt} in terms of hh by relating volume change to depth change. Then evaluate dhdt\dfrac{dh}{dt} when h=6.0h=6.0 m and the lubricant temperature is 20 °C. (d) Suppose an engineer neglected thermal expansion when estimating dhdt\dfrac{dh}{dt}. Would this omission cause the estimate to be too large, too small, or unbiased at h=6.0h=6.0 m? Provide a quantitative or qualitative justification based on your work in part (b).

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