At 360 K, the galvanic reaction MnO4−(aq)+8H+(aq)+5Fe2+(aq)→Mn2+(aq)+4H2O(l)+5Fe3+(aq) has a standard cell potential of E∘=0.74V. The reaction involves n=5 electrons. The mixture contains [MnO4−]=5.0mM, [Mn2+]=0.20M, [Fe2+]=0.10M, [Fe3+]=0.50M, and [H+]=0.010M. Calculate the cell potential, E, at 360 K. (Constants: R=8.314Jmol−1K−1, F=9.65×104Cmol−1.)