The mass , in grams, of a tumor satisfies . At months, the mass is grams and…

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

The mass M(t)M(t), in grams, of a tumor satisfies dMdt=kM\dfrac{dM}{dt}=kM. At t=2t=2 months, the mass is 88 grams and increasing at a rate of 1.21.2 grams per month. What is the instantaneous growth rate of the tumor at t=5t=5 months? (a) 1.2 g/month1.2\text{ g/month} (b) 1.6 g/month1.6\text{ g/month} (c) 1.9 g/month1.9\text{ g/month} (d) 2.4 g/month2.4\text{ g/month}

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