MATHEMATICS · Multi-part · AP · AP Precalculus · Trigonometric and Polar Functions · Trigonometric and Polar Functions
Problem
Let x be any real number such that 0<x<1.
(i) Explain why both arcsinx and arctanx lie in the interval (0,2π).
(ii) Prove that arcsinx>arctanx for every x in (0,1).
(iii) Determine whether there exists a value of x in (0,1) for which arcsinx=arctanx. Justify your answer.