The specific heat of water = and the latent heat of ice =

PHYSICS · Single correct · A Level · Physics · Further mechanics and thermal physics · Further mechanics and thermal physics

Problem

The specific heat of water = 4200 J kg−1 K−14200 \text{ J kg}^{-1} \text{ K}^{-1} and the latent heat of ice = 3.4×105 J kg−13.4 \times 10^5 \text{ J kg}^{-1} . 100 grams of ice at 0∘C0^\circ\text{C} is placed in 200 g of water at 25∘C25^\circ\text{C} . The amount of ice that will melt as the temperature of water reaches 0∘C0^\circ\text{C} is close to (in grams): (1) 61.7 (2) 63.8 (3) 69.3 (4) 64.6

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