Find the equation of the line tangent to the curve at the point

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

Find the equation of the line tangent to the curve x2y−y3=10x^2y-y^3=10 at the point (2,1)(2,1). Express your answer in point–slope form. (a) y−1=43(x−2)y-1=\dfrac{4}{3}(x-2) (b) y−1=−14(x−2)y-1=-\dfrac{1}{4}(x-2) (c) y−1=−4(x−2)y-1=-4(x-2) (d) y−1=4(x−2)y-1=4(x-2)

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