When liquid medicine of density is to be put in the eye

PHYSICS · Single correct · CBSE · Physics · Mechanical Properties of Fluids · Mechanical Properties of Fluids

Problem

When liquid medicine of density ρ\rho is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension TT when the radius of the drop is RR . When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If r=5×10−4 mr = 5 \times 10^{-4} \text{ m} , ρ=103 kg m−3\rho = 10^3 \text{ kg m}^{-3} , g=10 ms−2g = 10 \text{ ms}^{-2} , T=0.11 Nm−1T = 0.11 \text{ Nm}^{-1} , the radius of the drop when it detaches from the dropper is approximately: (A) 1.4×10−3 m1.4 \times 10^{-3} \text{ m} (B) 3.3×10−3 m3.3 \times 10^{-3} \text{ m} (C) 2.0×10−3 m2.0 \times 10^{-3} \text{ m} (D) 4.1×10−6 m4.1 \times 10^{-6} \text{ m}

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