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MATHEMATICS · Single correct · AP · Calculus AB · Differentiation: Composite, Implicit, and Inverse Functions · Differentiation: Composite, Implicit, and Inverse Functions
Problem Determine d y d x \dfrac{dy}{dx} d x d y for y = x e x 2 sin 2 x y=x\,e^{x^{2}}\sin 2x y = x e x 2 sin 2 x .
(a) e x 2 [ sin 2 x ( 1 + x 2 ) + 2 x cos 2 x ] e^{x^{2}}\bigl[\sin 2x\,(1+x^{2})+2x\cos 2x\bigr] e x 2 [ sin 2 x ( 1 + x 2 ) + 2 x cos 2 x ]
(b) e x 2 [ sin 2 x ( 1 + 2 x 2 ) + 2 x cos 2 x ] e^{x^{2}}\bigl[\sin 2x\,(1+2x^{2})+2x\cos 2x\bigr] e x 2 [ sin 2 x ( 1 + 2 x 2 ) + 2 x cos 2 x ]
(c) e x 2 [ sin 2 x + 2 x cos 2 x ] e^{x^{2}}\bigl[\sin 2x+2x\cos 2x\bigr] e x 2 [ sin 2 x + 2 x cos 2 x ]
(d) e x 2 [ sin 2 x ( 1 + 2 x 2 ) − 2 x cos 2 x ] e^{x^{2}}\bigl[\sin 2x\,(1+2x^{2})-2x\cos 2x\bigr] e x 2 [ sin 2 x ( 1 + 2 x 2 ) − 2 x cos 2 x ]
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