Under an adiabatic process

PHYSICS · Single correct · CBSE · Physics · Kinetic Theory · Kinetic Theory

Problem

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecule changes from

\tau_1

\tau_2

. If

\frac{C_p}{C_v} = \gamma

for this gas then a good estimate for

\frac{\tau_2}{\tau_1}

is given by: (1) 2 (2)

\frac{1}{2}

(3)

\left(\frac{1}{2}\right)^\gamma

(4)

\left(\frac{1}{2}\right)^{\frac{\gamma+1}{2}}