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MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions
Problem Determine the coordinates of the point on the unit circle that corresponds to θ = 240 ∘ θ = 240^{\circ} θ = 24 0 ∘ ( − 1 2 , 3 2 ) \left(-\dfrac{1}{2},\; \dfrac{\sqrt3}{2}\right) ( − 2 1 , 2 3 ) ( − 3 2 , − 1 2 ) \left(-\dfrac{\sqrt3}{2},\; -\dfrac{1}{2}\right) ( − 2 3 , − 2 1 ) ( − 1 2 , − 3 2 ) \left(-\dfrac{1}{2},\; -\dfrac{\sqrt3}{2}\right) ( − 2 1 , − 2 3 ) ( 1 2 , − 3 2 ) \left(\dfrac{1}{2},\; -\dfrac{\sqrt3}{2}\right) ( 2 1 , − 2 3 ) Browse the problem library