Find the limiting points of the circles and show that the square of the distance…

MATHEMATICS · Subjective · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

Find the limiting points of the circles (x2+y2+2gx+c)+λ(x2+y2+2fy+d)=0(x^2 + y^2 + 2gx + c) + \lambda (x^2 + y^2 + 2fy + d) = 0 and show that the square of the distance between them is (c−d)2−4f2g2+4cf2+4dg2f2+g2\frac{(c-d)^2 - 4f^2g^2 + 4cf^2 + 4dg^2}{f^2 + g^2}

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