If and , then the area bounded by and the curve is equal…

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Integrals · Applications of Integrals

Problem

If f(x)=x−1f(x)=x-1 and g(x)=∣f(∣x∣)−2∣g(x)=|f(|x|)-2|, then the area bounded by y=g(x)y=g(x) and the curve x2−4y+8=0x^2-4y+8=0 is equal to (1) 43(42−5)\frac{4}{3}(4\sqrt{2}-5) (2) 83(42−3)\frac{8}{3}(4\sqrt{2}-3) (3) 43(42−3)\frac{4}{3}(4\sqrt{2}-3) (4) 83(42−5)\frac{8}{3}(4\sqrt{2}-5)

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