Let be the -periodic extension to of the function defined on the interval by

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Let pp be the 22-periodic extension to R\mathbb{R} of the function defined on the interval [−1,1][-1,1] by p(x)=∣x∣p(x)=|x|. In other words, p(x+2)=p(x)p(x+2)=p(x) for all xx, and p(x)=∣x∣p(x)=|x| on [−1,1][-1,1]. (a) Prove that pp is continuous on R\mathbb{R}. (b) Identify all real numbers cc at which pp fails to be differentiable. Provide a rigorous justification that directly evaluates the one-sided limits of the difference quotient at each such cc. (c) For a point aa at which pp is differentiable, compute p′(a)p'(a) in closed form. Express your answer as a function of aa defined over the appropriate domain.

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