Let be a polynomial one-one function such that f(x)f(y) + 2 = f(x) + f(y) + f(xy)

MATHEMATICS · Single correct · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Let f(x)f(x) be a polynomial one-one function such that f(x)f(y)+2=f(x)+f(y)+f(xy),∀x,y∈R−{0},f(x)f(y) + 2 = f(x) + f(y) + f(xy), \forall x, y \in R - \{0\}, f(1)≠1,f′(1)=3.f(1) \neq 1, f'(1) = 3. Let g(x)=x4(f(x)+3)−∫0xf(t)dtg(x) = \frac{x}{4}(f(x) + 3) - \int_0^x f(t) dt , then (1) g(x)=0g(x) = 0 has exactly one root for x∈(0,1)x \in (0, 1) (2) g(x)=0g(x) = 0 has exactly two roots for x∈(0,1)x \in (0, 1) (3) g(x)≠0,∀x∈R−{0}g(x) \neq 0, \forall x \in R - \{0\} (4) g(x)=0,∀x∈R−{0}g(x) = 0, \forall x \in R - \{0\}

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