A reaction follows the elementary slow step

CHEMISTRY · Single correct · AP · Chemistry · Kinetics · Kinetics

Problem

A reaction follows the elementary slow step A(g)+2B(g)→productsA(\text{g}) + 2B(\text{g}) \to \text{products}, and its rate law is found to be rate=k[A][B]2\text{rate} = k[A][B]^2. A 1.0 L1.0\,\text{L} reaction mixture initially contains [A]=0.50 M[A] = 0.50\,\text{M} and [B]=0.30 M[B] = 0.30\,\text{M}. An inert solvent is then added to double the volume of the mixture to 2.0 L2.0\,\text{L} with no loss of reactants. Which option best describes the new initial rate compared with the original? (a) It is one-quarter of the original rate. (b) It is equal to the original rate. (c) It is one-eighth of the original rate. (d) It is one-half of the original rate.

Related theory

Browse the problem library