The lowest-energy orbit of the electron in a lithium ion (nuclear charge ) can be…

CHEMISTRY · Single correct · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

The lowest-energy orbit of the electron in a lithium ion

\text{Li}^{2+}

(nuclear charge

+3e

) can be expressed in terms of the Bohr radius

a_{0}=5.29\times10^{-11}\,\text{m}

. What is the radius of this orbit? (a)

5.3\times10^{-11}\,\text{m}

(b)

5.9\times10^{-12}\,\text{m}

(c)

1.8\times10^{-11}\,\text{m}

(d)

7.1\times10^{-11}\,\text{m}