The position of a particle as a function of time

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

The position of a particle as a function of time tt, is given by x(t)=at+bt2−ct3x(t) = at + bt^2 - ct^3 where, a,ba, b and cc are constants. When the particle attains zero acceleration, then its velocity will be: (1) a+b24ca + \frac{b^2}{4c} (2) a+b23ca + \frac{b^2}{3c} (3) a+b2ca + \frac{b^2}{c} (4) a+b22ca + \frac{b^2}{2c}

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