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MATHEMATICS · Multi correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

If xcos⁡α+ysin⁡α=xcos⁡β+ysin⁡β=2ax\cos\alpha+y\sin\alpha=x\cos\beta+y\sin\beta=2a, where 0<α,β<π20<\alpha,\beta<\dfrac{\pi}{2}, then (1) cos⁡α+cos⁡β=4axx2+y2\cos\alpha+\cos\beta=\dfrac{4ax}{x^2+y^2} (2) cos⁡αcos⁡β=4a2−y2x2+y2\cos\alpha\cos\beta=\dfrac{4a^2-y^2}{x^2+y^2} (3) sin⁡α+sin⁡β=4ayx2+y2\sin\alpha+\sin\beta=\dfrac{4ay}{x^2+y^2} (4) sin⁡αsin⁡β=4a2−x2x2+y2\sin\alpha\sin\beta=\dfrac{4a^2-x^2}{x^2+y^2}

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