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Answer the following:
PHYSICS · Multi-part · ISC · Physics · Kinematics · Laws of Motion
Problem
Answer the following: (a) Show that
sin
2
θ
1
−
sin
2
θ
=
tan
2
θ
\dfrac{\sin^2 \theta}{1 - \sin^2 \theta} = \tan^2 \theta
1
−
sin
2
θ
sin
2
θ
=
tan
2
θ
for any acute angle
θ
\theta
θ
. (b) Hence, evaluate
sin
2
30
∘
1
−
sin
2
30
∘
\dfrac{\sin^2 30^\circ}{1 - \sin^2 30^\circ}
1
−
sin
2
3
0
∘
sin
2
3
0
∘
.
Related theory
Newton's Second Law & Dynamics
Kinematic Equations for Uniform Acceleration
Kinematic Equations
Mathematical formulation of Second Law
Newton's second law
Equations of motion
Laws of Motion
Newton's laws of motion
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