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MATHEMATICS · Subjective · CBSE · Mathematics · Determinants · Determinants
Problem If f ( x ) = ∣ x + c 1 x + a x + a x + b x + c 2 x + a x + b x + b x + c 3 ∣ f(x)=\left|\begin{matrix}x+c_1 & x+a & x+a\\ x+b & x+c_2 & x+a\\ x+b & x+b & x+c_3\end{matrix}\right| f ( x ) = x + c 1 x + b x + b x + a x + c 2 x + b x + a x + a x + c 3 f ( x ) f(x) f ( x ) x x x f ( 0 ) = b g ( a ) − a g ( b ) ( b − a ) f(0)=\frac{bg(a)-ag(b)}{(b-a)} f ( 0 ) = ( b − a ) b g ( a ) − a g ( b ) g ( x ) = ( c 1 − x ) ( c 2 − x ) ( c 3 − x ) g(x)=(c_1-x)(c_2-x)(c_3-x) g ( x ) = ( c 1 − x ) ( c 2 − x ) ( c 3 − x ) Browse the problem library