At 600 K, the equilibrium constant for the reaction is . What is the value of the…

CHEMISTRY · Single correct · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

At 600 K, the equilibrium constant for the reaction 12 N2(g)+32 H2(g)⇌NH3(g)\tfrac12\,\text{N}_2(g)+\tfrac32\,\text{H}_2(g)\rightleftharpoons\text{NH}_3(g) is K1=6.0×102K_1=6.0\times10^{2}. What is the value of the equilibrium constant for the reaction written as N2(g)+3 H2(g)⇌2 NH3(g)\text{N}_2(g)+3\,\text{H}_2(g)\rightleftharpoons2\,\text{NH}_3(g) (a) 1.2×1031.2\times10^{3} (b) 3.6×1043.6\times10^{4} (c) 3.6×1053.6\times10^{5} (d) 2.5×1012.5\times10^{1}

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