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For the reversible reaction
CHEMISTRY · Subjective · AP · Chemistry · Kinetics · Kinetics
Problem
For the reversible reaction
E
⇌
F
E \rightleftharpoons F
E
⇌
F
, the instantaneous rates (in
M
⋅
s
−
1
\text{M}\cdot\text{s}^{-1}
M
⋅
s
−
1
) vary with time
t
t
t
(in
s
s
s
) according to
rate
forward
=
0.60
e
−
0.08
t
\text{rate}_{\text{forward}} = 0.60\, e^{-0.08t}
rate
forward
=
0.60
e
−
0.08
t
rate
reverse
=
0.60
(
1
−
e
−
0.08
t
)
\text{rate}_{\text{reverse}} = 0.60\, \left(1 - e^{-0.08t}\right)
rate
reverse
=
0.60
(
1
−
e
−
0.08
t
)
Calculate the time at which the system first reaches equilibrium.
Related theory
Rate of Reaction
Chemical Kinetics
Rate of a Chemical Reaction
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