The inverse tangent function admits the series representation x = _ k=0 ^ (-1)^k x^…

MATHEMATICS · Multi-part · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

The inverse tangent function admits the series representation arctan⁡x=∑k=0∞(−1)kx2k+12k+1,∣x∣≤1.\arctan x = \sum_{k=0}^{\infty}(-1)^k\frac{x^{2k+1}}{2k+1},\qquad |x|\le 1. Answer the following questions concerning numerical approximations derived from this series. (a) Verify that, for ∣x∣≤1|x|\le 1, the absolute values of consecutive non-zero terms of the series decrease whenever k≥0k\ge 0. Clearly indicate any inequalities you employ. (b) For x=13x=\tfrac13, determine the least integer nn such that truncating the series after the nn-th non-zero term guarantees an absolute error below 10−510^{-5}. Provide the resulting numerical approximation of arctan⁡(13)\arctan(\tfrac13) rounded to eight decimal places. (c) Let S3(x)S_3(x) denote the degree-3 polynomial obtained by keeping the first two non-zero terms of the series (through x3x^{3}). Identify all real numbers xx in [−1,1][-1,1] for which the absolute error ∣arctan⁡x−S3(x)∣|\arctan x-S_3(x)| is smaller than 0.010.01. Present your solution as an interval or union of intervals, and justify every inequality used in your reasoning.

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