The reversible reaction PCl₅(g) ⇌ PCl₃(g) + Cl₂(g) (at ) is carried out in a rigid…

CHEMISTRY · Multi-part · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

The reversible reaction PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)  Kc=1.80K_c = 1.80 (at 523 K523\,\text{K}) is carried out in a rigid reaction vessel at 523 K523\,\text{K}. The mixture is allowed to reach equilibrium, after which a portion of Cl₂ is removed rapidly at t=1 mint = 1\,\text{min}. A record of the concentrations following the disturbance is given below. Concentration Data (all units = mol L−1\text{mol L}^{-1})
Time (min)[PCl₅][PCl₃][Cl₂]
0 (just before Cl₂ removal)0.2000.3001.20
1 (immediately after Cl₂ removal)0.2000.3000.60
50.1800.3200.68
100.1600.3400.76
150.1500.3500.80
(1) Part 1: (a) Calculate the value of the reaction quotient QcQ_c at t=5 mint = 5\,\text{min}. Indicate whether the net reaction is proceeding in the forward or reverse direction during the interval just after t=5 mint = 5\,\text{min}. (2) Part 2: (b) Repeat the QcQ_c calculation for t=10 mint = 10\,\text{min}. Compare the value of QcQ_c at 10 min10\,\text{min} with that at 5 min5\,\text{min} and with KcK_c, and state whether the system is closer to or farther from equilibrium at 10 min10\,\text{min}. (3) Part 3: (c) Using the concentration data provided, determine the earliest time after the disturbance at which the system can be considered to have re-established equilibrium. Justify your answer quantitatively.

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