When solving the quadratic equation for the time of flight of a ball thrown…

PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation

Problem

When solving the quadratic equation for the time of flight of a ball thrown vertically upward so that the displacement becomes zero again, two roots are obtained: t=0 st = 0\,\text{s} and t=4 st = 4\,\text{s}. Why is the root t=0 st = 0\,\text{s} not taken as the answer? (a) Because substituting t=0 st=0\,\text{s} makes the calculated displacement negative, so it cannot be accepted. (b) It represents the instant of projection itself, not the later instant asked for. (c) Because at t=0 st=0\,\text{s} the velocity would come out to be zero, contradicting the fact that the ball was thrown upward. (d) Choosing t=0 st=0\,\text{s} would violate conservation of energy by making the ball start with no kinetic energy.

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