PHYSICS · Multi-part · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance
Problem
A rectangular sheet of copper of mass 11g, density 8.9gcm−3, and uniform thickness 0.20mm is cut into two identical square plates which are then assembled, with their faces parallel and separated by 0.50mm of air, to form a capacitor. Take ε0=8.85×10−12C2N−1m−2.
(i) Determine the length of the side of each square plate.
(ii) Calculate the capacitance of the capacitor thus formed.
(iii) The capacitor is charged to a potential difference of 200V. Find the energy stored in it.
(iv) A plastic dielectric of relative permittivity 3.0 completely fills the space between the plates without altering the separation. Calculate the percentage increase in the energy stored when the same potential difference of 200V is applied.