Consider the function h(x)= cases |x| x , & x 0

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Consider the function h(x)={∣x∣x,x≠0,k,x=0.h(x)= \begin{cases} \dfrac{|x|}{x}, & x\neq0,\\ k, & x=0. \end{cases} Which of the following statements about the continuity of hh at x=0x=0 is correct? (a) Continuous if k=0k=0 (b) Continuous if k=1k=1 (c) Not continuous for any real kk (d) Continuous if k=−1k=-1

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