Calculate the wavelength of the photon emitted when an electron in a hydrogen atom…

PHYSICS · Single correct · CBSE · Physics · Atoms · Atoms

Problem

Calculate the wavelength of the photon emitted when an electron in a hydrogen atom drops from the n=4n=4 state to the n=2n=2 state. Constants: En=−13.6 eV/n2E_n=-13.6\,\text{eV}/n^2, h=6.63×10−34 J sh=6.63\times10^{-34}\,\text{J\,s}, c=3.00×108 m/sc=3.00\times10^{8}\,\text{m/s}, 1 eV=1.60×10−19 J1\,\text{eV}=1.60\times10^{-19}\,\text{J}. (a) 9.75×101 nm9.75\times10^{1}\,\text{nm} (b) 3.66×102 nm3.66\times10^{2}\,\text{nm} (c) 4.88×102 nm4.88\times10^{2}\,\text{nm} (d) 9.74×102 nm9.74\times10^{2}\,\text{nm}

Related theory

Browse the problem library