Calculate the magnetic field inside a solenoid of turns

PHYSICS · Single correct · CBSE · Physics · Magnetic Effects of Electric Current · Magnetic Effects of Electric Current

Problem

Calculate the magnetic field inside a solenoid of 800800 turns, length 0.20 m0.20\,\text{m}, carrying a current of 3.0 A3.0\,\text{A}. (Take μ0=4π×10−7 T m A−1\mu_0 = 4\pi \times 10^{-7}\,\text{T m A}^{-1}.) (a) 7.5×10−3 T7.5 \times 10^{-3}\,\text{T} (b) 1.5×10−2 T1.5 \times 10^{-2}\,\text{T} (c) 1.5×10−3 T1.5 \times 10^{-3}\,\text{T} (d) 3.0×10−2 T3.0 \times 10^{-2}\,\text{T}

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