A proton of speed enters a magnetic field at an angle of

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Magnetism and Electromagnetism · Magnetism and Electromagnetism

Problem

A proton of speed 1.0×107 m s−11.0\times10^{7}\,\text{m s}^{-1} enters a 0.20 T0.20\,\text{T} magnetic field at an angle of 60∘60^{\circ}. After completing exactly five turns of its helical trajectory, the total length of the path traced by the proton is closest to (a) 14.2 m14.2\,\text{m} (b) 16.4 m16.4\,\text{m} (c) 8.7 m8.7\,\text{m} (d) 20.0 m20.0\,\text{m}

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