CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

\frac{d}{dx} \left[ \frac{2}{\pi} \sin x^0 \right] =

(a)

\frac{\pi}{180} \cos x^0

(b)

\frac{1}{90} \cos x^0

(c)

\frac{\pi}{90} \cos x^0

(d)

\frac{2}{90} \cos x^0