Define by , where is a real parameter. The function is bijective precisely…

MATHEMATICS · Single correct · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

Define f:R∖{−1}→R∖{p}f:\mathbb{R}\setminus\{-1\}\to\mathbb{R}\setminus\{p\} by f(x)=px+2x+1f(x)=\dfrac{px+2}{x+1}, where pp is a real parameter. The function ff is bijective precisely when (a) p=2p=2 (b) p≠2p\ne 2 (c) p=1p=1 (d) p≠12p\ne\dfrac12

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