Let for , and let g(x)= cases x (1+ 1 x ),&0<x 1, 0,&x=0. cases Then _ n f ( 1n )f (…

MATHEMATICS · Single correct · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Let f(x)=(1+1x)xf(x)=\left(1+\frac{1}{x}\right)^x for x>0x>0, and let g(x)={xln⁡(1+1x),0<x≤1,0,x=0.g(x)=\begin{cases}x\ln\left(1+\frac{1}{x}\right),&0<x\leq1,\\0,&x=0.\end{cases} Then lim⁡n→∞{f(1n)f(2n)f(3n)⋯f(nn)}1/n\lim_{n\to\infty}\left\{f\left(\frac1n\right)f\left(\frac2n\right)f\left(\frac3n\right)\cdots f\left(\frac nn\right)\right\}^{1/n} equals (1) 2e\sqrt{2}e (2) 2e\sqrt{2e} (3) 2e2\sqrt{e} (4) e\sqrt{e}

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