Consider the region bounded above by the horizontal line

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Consider the region bounded above by the horizontal line y=2y=2, below by the line y=x−1y=x-1, and between x=0x=0 and x=2x=2. The region is revolved about the x-axis. Which of the following best describes the integral setup needed to compute the volume of the solid? (a) V=π∫02[22−∣x−1∣2] dxV=\pi\int_{0}^{2}\bigl[2^{2}-|x-1|^{2}\bigr]\,dx (b) V=π[∫0122 dx+∫12(22−(x−1)2) dx]V=\pi\left[\int_{0}^{1}2^{2}\,dx+\int_{1}^{2}\bigl(2^{2}-(x-1)^{2}\bigr)\,dx\right] (c) V=π∫0222 dxV=\pi\int_{0}^{2}2^{2}\,dx (d) V=π∫02[22−(x−1)2] dxV=\pi\int_{0}^{2}\bigl[2^{2}-(x-1)^{2}\bigr]\,dx

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