A solid ball of radius has a charge density given by for

PHYSICS · Single correct · AP · Physics C: Electricity and Magnetism · Electric Charges Fields and Gauss's Law · Electric Charges Fields and Gauss's Law

Problem

A solid ball of radius RR has a charge density ρ\rho given by ρ=ρ0(1−rR)\rho = \rho_0 \left( 1 - \frac{r}{R} \right) for 0≤r≤R0 \le r \le R . The electric field outside the ball is: (1) ρ0R3ϵ0r2\frac{\rho_0 R^3}{\epsilon_0 r^2} (2) 4ρ0R33ϵ0r2\frac{4\rho_0 R^3}{3\epsilon_0 r^2} (3) 3ρ0R34ϵ0r2\frac{3\rho_0 R^3}{4\epsilon_0 r^2} (4) ρ0R312ϵ0r2\frac{\rho_0 R^3}{12\epsilon_0 r^2}

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