A shot-put athlete launches the iron ball so that it lands again on ground level

PHYSICS · Multi-part · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

A shot-put athlete launches the iron ball so that it lands again on ground level,

80\,\text{m}

away from the point of release. The ball attains a maximum height of

20\,\text{m}

during its flight. Proceed to answer the following: (a) Show that the angle of projection

\theta_0

satisfies

\tan\theta_0=\dfrac{4H}{R}

, where

H

is the maximum height and

R

is the horizontal range. (b) Using the numerical values given, calculate

\theta_0

correct to the nearest degree. (c) Determine the initial speed

v_0

of the ball, taking

g = 9.8\,\text{m s}^{-2}

. (d) Comment, with reason, on whether a second value of

\theta_0

is possible for the same pair

(H, R)