A particle moves along a straight track

MATHEMATICS · Multi-part · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

A particle moves along a straight track. Its velocity at time tt seconds is given by v(t)=6t2−4t+1  m s−1,v(t)=6t^{2}-4t+1\;\text{m s}^{-1}, and its position at t=0t=0 is 3  m3\;\text{m} from a fixed origin. (a) Find the position function s(t)s(t) of the particle. (b) Determine the acceleration of the particle at t=2 st=2\text{ s}. (c) Compute the total displacement of the particle during the first 33 seconds of motion.

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